Map family's table column to Inventor property

By Adam Nagy

When trying to figure out how to do something in the Inventor API, then almost always the best way to go is: do it in the UI, investigate in the API.

So I registered in the Content Center my own part, created a SIZE property then mapped it to Project.Description (Design Tracking Properties:Description):

Now using the API I can find out how the SIZE property got mapped to Project.Description property:

Public Sub CCtest()
  Dim cc As ContentCenter
  Set cc = ThisApplication.ContentCenter
  
  Dim ctvn As ContentTreeViewNode
  Set ctvn = cc.TreeViewTopNode. _
    ChildNodes("Features"). _
    ChildNodes("English"). _
    ChildNodes("Block")
    
  Dim cf As ContentFamily
  Set cf = ctvn.Families(1)
  
  Dim ctc As ContentTableColumn
  Set ctc = cf.TableColumns("Size")
  
  If ctc.HasPropertyMap Then
    Dim psid As String
    Dim pid As String
    Call ctc.GetPropertyMap(psid, pid)
    Debug.Print "PropertySetId = " & psid
    Debug.Print "PropertyId = " & pid
  End If
End Sub

Result:

PropertySetId = {32853F0F-3444-11d1-9E93-0060B03C1CA6}
PropertyId = 29

So basically you just have to look for the given property set in Document.PropertySets and use its InternalName property, then look for the property inside it and use the Property's PropId.